Role of Natural Resources and Environmental Protection Volunteer in the operation of natural resources and the environment of Samut Prakan Province.

Abstract

This research aims to achieve the following objectives: 1) To examine the roles of Natural Resources and Environmental Protection Volunteers in carrying out activities related to natural resource and environmental conservation. 2) To Identify the challenges faced by Natural Resources and Environmental Protection Volunteers in fulfilling their roles and responsibilities. And 3) To explore the perspectives on enhancing the effectiveness of Natural Resources and Environmental Protection Volunteers’ roles in community-based natural resource and environmental conservation efforts. This quantitative research employed a survey method to collect data from 383 persons of Simple Random Sampling. Natural Resources and Environmental Protection Volunteers in Samut Prakan Province, Thailand, during the year 2020. The instrument used in the study was a questionnaire. (Questionnaire) Statistics used in data analysis are frequency distribution,  percentage,  mean, standard deviation, and hypothesis testing using t-test (Independent Sample) and F-test (One Way ANOVA) statistics. Findings: 1) Work Performance of Natural Resources and Environmental Protection Volunteers in executing their roles in natural resource and environmental conservation activities in Samut Prakan Province Overall, the average is at a high level (𝑥̅ =3.73, S.D.=0.76). 2) In terms of issues and obstacles encountered during the execution of their roles, the Natural Resources and Environmental Protection Volunteers in natural resource and environmental conservation activities in Samut Prakan Province Overall, the average is at a moderate level (𝑥̅ =3.47, S.D.=1.04). 3) Regarding the perspectives on the development of the roles of Natural Resources and Environmental Protection Volunteers in natural resource and environmental conservation activities in Samut Prakan Province, Overall, the average is at a high level (𝑥̅ =3.58, S.D.=0.92).